在好例子网，分享、交流、成长！
您当前所在位置：首页 → C/C++ 开发实例 → Android手机应用开发 → “欢乐五子棋”——C++程序设计

“欢乐五子棋”——C++程序设计

Android手机应用开发

下载此实例
  • 开发语言：C/C++
  • 实例大小：0.01M
  • 下载次数：9
  • 浏览次数：206
  • 发布时间：2019-10-08
  • 实例类别：Android手机应用开发
  • 发 布 人：kuangyy
  • 文件格式：.cpp
  • 所需积分：2
 相关标签： 五子棋
网友评论 举报投诉 收藏该页

实例介绍

【实例简介】“欢乐五子棋”——C 程序设计，使用a和b 代表 黑棋和白棋

【实例截图】

from clipboard

【核心代码】 

#include<iostream>
#include<cstdlib>
#include<conio.h>
#include<cstdio>
#include<windows.h>
//宏定义替换文本 
#define X coord1<0||coord1>14||int(coord1)!=coord1
#define Y coord2<0||coord2>14||int(coord2)!=coord2
#define ENTWRONG cout<<"\n输入错误.\n"; system("pause"); continue;
#define att pointer(x,y,i,1)==2&&

using namespace std;

void welcome();
void pvp();//玩家对战 
void pve();//人机对战
int judge();//胜负判断
void display();//打印屏幕 
int envaluate(int x,int y);//估值函数
int pointer(int x,int y,int face,int l);//获取指定点类型函数 
int situation[15][15];//存棋数组 
int coord1,coord2;//输入的坐标 
int flag=0;//胜负标志变量 
int main() 
{
	for(int st=0;st<15;  st)
		for(int nd=0;nd<15;  nd) 
			situation[st][nd]=0;//数组初始化 
	welcome();
	cout<<"游戏结束.";
	if(flag==1) cout<<"玩家1胜利\n";
	else if(flag==2) cout<<"玩家2胜利\n";
	else if(flag==3) cout<<"平局\n";
	system("pause"); 
	return 0;
}

void welcome()
{
	char ch;
	cout<<"欢迎使用五子棋\n"<<"按0退出，按1玩家对战，按2人机对战\n";
	do{
	ch=getch();
	if(ch=='0') exit(0);
	else if(ch=='1') pvp();
	else if(ch=='2') pve();
	else cout<<"请按下正确的按键\n"; 
	}while(ch!='0'&&ch!='1'&&ch!='2');
}

void pvp()
{ 
	do{
		for(;;){//死循环直到输入正确 
			display();
			cout<<"\n请玩家1输入下棋点纵坐标：";
			cin>>coord1;
			if(X){ENTWRONG}
			cout<<"\n请玩家1输入下棋点横坐标：";
			cin>>coord2;
			if(Y){ENTWRONG}
			if(situation[coord1][coord2]!=0){
				ENTWRONG
			}
			situation[coord1][coord2]=1;
			break;
			}	
				if((flag=judge())!=0) break;
				for(;;){
					display();
					cout<<"\n请玩家2输入下棋点纵坐标：";
					cin>>coord1;
					if(X){ENTWRONG}
					cout<<"\n请玩家2输入下棋点横坐标：";
					cin>>coord2;
					if(Y){ENTWRONG}
					if(situation[coord1][coord2]!=0){
						ENTWRONG
					}
					situation[coord1][coord2]=2;
					break;
			}
	}while((flag=judge())==0);
}

void pve()//AI为玩家2，用户为玩家1 
{
	int bestcoord1,bestcoord2;
	int max,value;
	do{
	for(;;){//死循环直到输入正确 
		display();
		cout<<"\n请玩家输入下棋点纵坐标：";
		cin>>coord1;
		if(X){ENTWRONG}
		cout<<"\n请玩家输入下棋点横坐标：";
		cin>>coord2;
		if(Y){ENTWRONG}
		if(situation[coord1][coord2]!=0){
			ENTWRONG
		}
		situation[coord1][coord2]=1;
		break;
		}
	for(int st=0;st<15;  st){
		for(int nd=0;nd<15;  nd){
			if(situation[st][nd]==0) value=envaluate(st,nd);
			if(value>max){
				max=value;
				bestcoord1=st,bestcoord2=nd;
			}
		}
	}
	situation[bestcoord2][bestcoord1]=2;
	}while((flag=judge())==0);
}

void display()
{
	system("cls");//清空屏幕 
	for(int st=0;st<15;  st){
		for(int nd=0;nd<15;  nd){
			if(situation[st][nd]==0) cout<<"  ";
			else if(situation[st][nd]==1) cout<<'a';
			else if(situation[st][nd]==2) cout<<'b';
		}
		cout<<endl;
	}//遍历数组并打印棋盘 
	cout<<endl<<"左上角第一个点的坐标为(0,0)\n";
}

/*int judge()				
{
	for(int i=1;i<=8;  i){
		for(int st=0;st<15;  st){
			for(int nd=0;nd<15;  nd){
				if(situation[st][nd]==pointer(st,nd,i,1)&&pointer(st,nd,i,1)==pointer(st,nd,i,2)&&pointer(st,nd,i,2)==pointer(st,nd,i,3)&&pointer(st,nd,i,3)==pointer(st,nd,i,4))
					if(situation[st][nd]==1) return 1;
					else if(situation[st][nd]==2) return 2;
			}
		}
	}
	int sum;
	for(int st=0;st<15;  st){
		for(int nd=0;nd<15;  nd){
			sum =situation[st][nd];
		}
	}
	if(sum==337) return 3;//棋盘下满，平局 
	return 0;
}*/
int judge()			 
{
	int a=0,b=0;
	for (int i=0;i<15;  i)			         //横向判断 
	{
		for (int h=0;h<10;  h)
		{
		if (situation[a][b]==situation[a 1][b]&&situation[a][b]==situation[a 2][b]&&situation[a][b]==situation[a 3][b]&&situation[a][b]==situation[a 4][b]&&situation[a][b]==1) return 1;			//1为玩家1胜利 
		else if (situation[a][b]==situation[a 1][b]&&situation[a][b]==situation[a 2][b]&&situation[a][b]==situation[a 3][b]&&situation[a][b]==situation[a 4][b]&&situation[a][b]==2) return 2;		//2为玩家2胜利 
		a  ;																																														//3为平局
		}	
		b  ;																													
	}
	a=b=0;
	for (int i=0;i<15;  i)				//纵向判断 
	{	
		for  (int h=0;h<10;  h)
		{
		if (situation[a][b]==situation[a][b 1]&&situation[a][b]==situation[a][b 2]&&situation[a][b]==situation[a][b 3]&&situation[a][b]==situation[a][b 4]&&situation[a][b]==1) return 1;
		else if (situation[a][b]==situation[a][b 1]&&situation[a][b]==situation[a][b 2]&&situation[a][b]==situation[a][b 3]&&situation[a][b]==situation[a][b 4]&&situation[a][b]==2) return 2;	
		b  ;
		}
		a  ;
	}
	a=b=0;
	for (int i=0;i<15;  i)				//右下方判断 
	{
		for (int h=0;h<10;  h)
		{
		if (a 1>15||a 2>15||a 3>15||a 4>15||b 1>15||b 2>15||b 3>15||b 4>15) break;
		if (situation[a][b]==situation[a 1][b 1]&&situation[a][b]==situation[a 2][b 2]&&situation[a][b]==situation[a 3][b 3]&&situation[a][b]==situation[a 4][b 4]&&situation[a][b]==1) return 1;
		if (situation[a][b]==situation[a 1][b 1]&&situation[a][b]==situation[a 2][b 2]&&situation[a][b]==situation[a 3][b 3]&&situation[a][b]==situation[a 4][b 4]&&situation[a][b]==2) return 2;
		b  ;
		}
		a  ;
	}
	a=b=0;
	for (int i=0;i<15;  i)				//左下方判断 
	{
		for (int h=0;h<10;  h)
		{
		if (a-1>15||a-2>15||a-3>15||a-4>15||b-1>15||b-2>15||b-3>15||b-4>15) break;
		if (situation[a][b]==situation[a-1][b-1]&&situation[a][b]==situation[a-2][b-2]&&situation[a][b]==situation[a-3][b-3]&&situation[a][b]==situation[a-4][b-4]&&situation[a][b]==1) return 1;
		if (situation[a][b]==situation[a-1][b-1]&&situation[a][b]==situation[a-2][b-2]&&situation[a][b]==situation[a-3][b-3]&&situation[a][b]==situation[a-4][b-4]&&situation[a][b]==2) return 2;
		b  ;
		}
		a  ;
	}
	int sum;
	for(int st=0;st<15;  st){
		for(int nd=0;nd<15;  nd){
			sum =situation[st][nd];
		}
	}
	if(sum==337) return 3;//棋盘下满，平局 
	return 0;
	
}
int pointer(int x,int y,int face,int l)
{//x,y是中心点,l是离中心点的距离 
 //face=1为上 2为下 3为左 4为右 5为左上 6为右上 7为左下 8为右下 
	if(face==1&&(y-l)>=0) return situation[y-l][x];
	else if(face==2&&(y l)<=14) return situation[y l][x];
	else if(face==3&&(x-l)>=0) return situation[y][x-l];
	else if(face==4&&(x l)<=14) return situation[y][x l];
	else if(face==5&&(x-l)>=0&&(y-l)>=0) return situation[y-l][x-l];
	else if(face==6&&(x l)<=14&&(y-l)<=14) return situation[y-l][x l];
	else if(face==7&&(x-l)>=0&&(y l)<=14) return situation[y l][x-l];
	else if(face==8&&(x l)<=14&&(y l)<=14) return situation[y 1][x 1];
	else return 0;
}

int envaluate(int x,int y)
{
	int value;//权重
	//进攻
	for(int i=1;i<=8;  i){
		//活四 
		if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,3)==pointer(x,y,i,4)&&pointer(x,y,i,5)==0) value =8;
		//冲四 
		else if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,3)==pointer(x,y,i,4)&&pointer(x,y,i,5)==1) value =7;
		else if(att pointer(x,y,i,-1)==pointer(x,y,i,1)&&pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)) value =7;
		else if(att pointer(x,y,i,-2)==pointer(x,y,i,-1)&&pointer(x,y,i,-1)==pointer(x,y,i,1)&&pointer(x,y,i,1)==pointer(x,y,i,2)) value =7;
		//活三 
		else if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,4)==0) value =6;
		else if(att pointer(x,y,i,1)==pointer(x,y,i,3)&&pointer(x,y,i,3)==pointer(x,y,i,4)&&pointer(x,y,i,2)==0&&pointer(x,y,i,5)==0) value =6;
		else if(att pointer(x,y,i,-1)==pointer(x,y,i,1)&&pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,-2)==0&&pointer(x,y,i,3)==0) value =6;
		else if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==pointer(x,y,i,1)&&pointer(x,y,i,5)==0) value =6;
		//眠三
		else if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,3)==1) value =5;
		else if(att pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==pointer(x,y,i,1)&&pointer(x,y,i,5)==1) value =5;
		else if(att pointer(x,y,i,-2)==pointer(x,y,i,-1)&&pointer(x,y,i,-1)==pointer(x,y,i,1)&&pointer(x,y,i,2)==0&&pointer(x,y,i,-3)==0) value =5; 
		else if(att pointer(x,y,i,1)==pointer(x,y,i,3)&&pointer(x,y,i,2)==0&&pointer(x,y,i,3)==pointer(x,y,i,4)&&pointer(x,y,i,5)==1) value =5;
		else if(att pointer(x,y,i,-1)==pointer(x,y,i,1)&&pointer(x,y,i,-2)==1&&pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,3)==1) value =5;
		else if(att pointer(x,y,i,-1)==1&&pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,4)==0&&pointer(x,y,i,5)==1) value =5;
		else if(pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,2)==pointer(x,y,i,-1)&&pointer(x,y,i,-1)==pointer(x,y,i,-2)) value =5;
		else if(att pointer(x,y,i,-1)==0&&pointer(x,y,i,-2)==pointer(x,y,i,1)&&pointer(x,y,i,-2)==pointer(x,y,i,-3)) value =5;
		else if(att pointer(x,y,i,1)==pointer(x,y,i,-1)&&pointer(x,y,i,1)==pointer(x,y,i,3)&&pointer(x,y,i,2)==0) value =5;
		//活二
		else if(pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,2)==pointer(x,y,i,3)&&pointer(x,y,i,4)==pointer(x,y,i,5)&&pointer(x,y,i,4)==0) value =4;
		else if(att pointer(x,y,i,-1)==0&&pointer(x,y,i,1)==pointer(x,y,i,2)&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==0) value =4;
		else if(att pointer(x,y,i,2)==0&&pointer(x,y,i,3)==2&&pointer(x,y,i,4)==0) value =4;
		else if(att pointer(x,y,i,2)==0&&pointer(x,y,i,-1)==2&&pointer(x,y,i,-2)==0) value =4;
		else if(att pointer(x,y,i,2)==0&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==2&&pointer(x,y,i,5)==0)	value =4;
		else if(pointer(x,y,i,1)==0&&pointer(x,y,i,-1)==2&&pointer(x,y,i,-2)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,3)==0) value =4;
		//眠二
		else if(pointer(x,y,i,1)==0&&pointer(x,y,i,2)==0&&pointer(x,y,i,3)==2&&pointer(x,y,i,4)==2&&pointer(x,y,i,5)==1) value =3;
		else if(pointer(x,y,i,-1)==0&&pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,3)==2&&pointer(x,y,i,4)==1) value =3;
		else if(pointer(x,y,i,-2)==0&&pointer(x,y,i,-1)==0&&pointer(x,y,i,1)==2&&pointer(x,y,i,2)==2&&pointer(x,y,i,3)==1) value =3;
		else if(pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==2&&pointer(x,y,i,5)==1) value =3;
		else if(pointer(x,y,i,-1)==0&&pointer(x,y,i,1)==2&&pointer(x,y,i,2)==0&&pointer(x,y,i,3)==2&&pointer(x,y,i,4)==1) value =3;
		else if(pointer(x,y,i,-3)==0&&pointer(x,y,i,-2)==0&&pointer(x,y,i,-1)==2&&pointer(x,y,i,1)==2&&pointer(x,y,i,2)==1) value =3;
		else if(pointer(x,y,i,1)==2&&pointer(x,y,i,2)==0&&pointer(x,y,i,3)==0&&pointer(x,y,i,4)==2&&pointer(x,y,i,5)==1) value =3;
		else if(pointer(x,y,i,-2)==0&&pointer(x,y,i,-1)==2&&pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2&&pointer(x,y,i,3)==1) value =3;
		else if(pointer(x,y,i,-1)==2&&pointer(x,y,i,1)==0&&pointer(x,y,i,2)==0&&pointer(x,y,i,3)==2) value =3;
		else if(pointer(x,y,i,-2)==2&&pointer(x,y,i,-1)==0&&pointer(x,y,i,1)==0&&pointer(x,y,i,2)==2) value =3;
		else value =2;//不属于这几种棋型的
		return value; 
		//防守略，思路相同 
		}
}

标签： 五子棋

实例下载地址

“欢乐五子棋”——C++程序设计

不能下载？内容有错？ 点击这里报错 + 投诉 + 提问

好例子网口号：伸出你的我的手 — 分享！

相关软件

相关文章

网友评论

我要评论

发表评论

(您的评论需要经过审核才能显示)

查看所有0条评论>>

小贴士

感谢您为本站写下的评论，您的评论对其它用户来说具有重要的参考价值，所以请认真填写。

  • 类似“顶”、“沙发”之类没有营养的文字，对勤劳贡献的楼主来说是令人沮丧的反馈信息。
  • 相信您也不想看到一排文字/表情墙，所以请不要反馈意义不大的重复字符，也请尽量不要纯表情的回复。
  • 提问之前请再仔细看一遍楼主的说明，或许是您遗漏了。
  • 请勿到处挖坑绊人、招贴广告。既占空间让人厌烦，又没人会搭理，于人于己都无利。

关于好例子网

本站旨在为广大IT学习爱好者提供一个非营利性互相学习交流分享平台。本站所有资源都可以被免费获取学习研究。本站资源来自网友分享，对搜索内容的合法性不具有预见性、识别性、控制性，仅供学习研究，请务必在下载后24小时内给予删除，不得用于其他任何用途，否则后果自负。基于互联网的特殊性，平台无法对用户传输的作品、信息、内容的权属或合法性、安全性、合规性、真实性、科学性、完整权、有效性等进行实质审查；无论平台是否已进行审查，用户均应自行承担因其传输的作品、信息、内容而可能或已经产生的侵权或权属纠纷等法律责任。本站所有资源不代表本站的观点或立场，基于网友分享，根据中国法律《信息网络传播权保护条例》第二十二与二十三条之规定，若资源存在侵权或相关问题请联系本站客服人员，点此联系我们。关于更多版权及免责申明参见 版权及免责申明

;
报警