使用C#实现的电子常用计算

【实例简介】可以实现常用无源器件的计算，比如电阻电容等，也有常用DCDC和LDO的计算。
【实例截图】
【核心代码】    class SerialParallelCalculation
    {
        static double _part1;
        static double _part2;
        static double _part3;
        static double _part4;
        static double _part5;
        static double _part6;
        static double _result;


        //public static double Part1 { get => _part1; set => _part1 = value; }
        //public static double Part2 { get => _part2; set => _part2 = value; }
        //public static double Part3 { get => _part3; set => _part3 = value; }
        //public static double Part4 { get => _part4; set => _part4 = value; }
        //public static double Part5 { get => _part5; set => _part5 = value; }
        //public static double Part6 { get => _part6; set => _part6 = value; }
        //public static double Result { get => _result; set => _result = value; }


        /// <summary>
        /// 求2个元件值的导数
        /// </summary>
        /// <param name="part1">元件1的值</param>
        /// <param name="part2">元件2的值</param>
        /// <param name="result">结果</param>
        public void Derivative(double part1, double part2, ref double result)
        {
            result = 1 / (1 / part1 1 / part2);
        }

        /// <summary>
        /// 求3个元件值的导数
        /// </summary>
        /// <param name="part1">元件1的值</param>
        /// <param name="part2">元件2的值</param>
        /// <param name="part3">元件3的值</param>
        /// <param name="result">结果</param>
        public void Derivative(double part1, double part2, double part3, ref double result)
        {
            result = 1 / (1 / part1 1 / part2 1 / part3);
        }

        /// <summary>
        /// 求4个元件值的导数
        /// </summary>
        /// <param name="part1">元件1的值</param>
        /// <param name="part2">元件2的值</param>
        /// <param name="part3">元件3的值</param>
        /// <param name="part4">元件4的值</param>
        /// <param name="result">结果</param>
        public void Derivative(double part1, double part2, double part3, double part4, ref double result)
        {
            result = 1 / (1 / part1 1 / part2 1 / part3 1 / part4);
        }

        /// <summary>
        /// 求5个元件值的导数
        /// </summary>
        /// <param name="part1">元件1的值</param>
        /// <param name="part2">元件2的值</param>
        /// <param name="part3">元件3的值</param>
        /// <param name="part4">元件4的值</param>
        /// <param name="part5">元件5的值</param>
        /// <param name="result">结果</param>
        public void Derivative(double part1, double part2, double part3, double part4, double part5, ref double result)
        {
            result = 1 / (1 / part1 1 / part2 1 / part3 1 / part4 1 / part5);
        }


        /// <summary>
        /// 求6个元件值的导数
        /// </summary>
        /// <param name="part1"></param>
        /// <param name="part2"></param>
        /// <param name="part3"></param>
        /// <param name="part4"></param>
        /// <param name="part5"></param>
        /// <param name="part6"></param>
        /// <param name="result"></param>
        public void Derivative(double part1, double part2, double part3, double part4, double part5, double part6, ref double result)
        {
            result = 1 / (1 / part1 1 / part2 1 / part3 1 / part4 1 / part5 1 / part6);
        }

        /// <summary>
        /// 求2个元件值的和
        /// </summary>
        /// <param name="part1">第一个元件的值</param>
        /// <param name="part2">第二个元件的值</param>
        /// <param name="result">结果</param>
        public void Summation(double part1, double part2, ref double result)
        {
            result = part1 part2;
        }


        public void Summation(double part1, double part2, double part3, ref double result)
        {
            result = part1 part2 part3;
        }



        public void Summation(double part1, double part2, double part3, double part4, ref double result)
        {
            result = part1 part2 part3 part4;
        }


        public void Summation(double part1, double part2, double part3, double part4, double part5, ref double result)
        {
            result = part1 part2 part3 part4 part5;
        }


        public void Summation(double part1, double part2, double part3, double part4, double part5, double part6, ref double result)
        {
            result = part1 part2 part3 part4 part5 part6;
        }
    }